using suitable identities solve these:
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Step-by-step explanation:
(i) (2y +5) (2y -5)
(2y)2-(5)2
4y2-25
(ii) (2y +3)(2y+ 3)
(2y +3)2
(2y)2 + (3)2 + 2×2y×3
4y2 + 9 + 12y
(iii) (2a-7)(2a-7)
(2a-7)2
(2a)2+ (7)2-2×2a×7
4a2 + 49- 28a
(iv) (2x+y)(2x +y)
(2x + y)2
(2x)2+ (y)2+2×2x×y
4x2 + y2+4xy