V= 2t² - 4t find acceleration at t = 3 secons.
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V= 2t² - 4t find acceleration at t = 3 secons.
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Answer:
v = 2t² - 4t
Now, dv/dt = a
So, dv/dt = 4t - 4
a = 4t - 4
Now, t = 3s
So, a = 4(3) - 4
a = 12 - 4
a = 8m/s²
Hope it helps you!!
Verified answer
Answer:
Given,
[tex]v = 2 {t}^{2} - 4t[/tex]
We have,
[tex]a = \frac{dv}{dt} [/tex]
So,
[tex]a(t) = \frac{d(2 {t}^{2} - 4t) }{dt} = 4t - 4[/tex]
Hence,
[tex]a(3) = 8m {s}^{ - 2} [/tex]