Vapour pressure of C6H6 and C7H8 mixture at 50°C is given by P (mm Hg) = 179XB + 92, where XB is the mole fraction of C6H6 . A solution is prepared by mixing 936 g benzene and 736 g toluene and if the vapours over this solution are removed and condensed into liquid and again brought to the temperature of 50°C, what would be mole fraction of C6H6 in the vapour state?
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