what is {(2÷2)×3}+1+2-1-2
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= {1×3}+3-3
= 3+3-3
= 6-3
= 3
Answer:
[(2 / 2) x 3 ] + 1+2 -1 -2
=[ 1 x 3 ] + 1 + 2 -1 -2
=(3) + 1 + 2 - 1 -2
=4 + 2 - 1 - 2
=6 - 1 - 2
=5 -2
= 3
= final answer is [3]
you can use the principal BODMAS
B = bracket
O = orders
D = division
M = multiplication
A = Addition
S = subtraction
Thanks.......!