what is the amount of H2 S o4 required to react completely with hundred litre of NH3 at ntp
what is the amount of H2 S o4 required to react completely with hundred litre of NH3 at ntp
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Dear Student,
◆ Answer -
21.86 g of H2SO4 will be required
● Explaination -
At NTP, moles of ammonia are -
n = V / 22.4
n = 10 / 22.4
n = 0.4462 mol
Reaction of H2SO4 with NH3 is represented by -
NH3 + ½ H2SO4 --> ½ (NH4)2SO4
From this 1 mol of NH3 reacts with ½ mol of H2SO4.
Hence, 0.4462 mol of NH3 will react with ½ × 0.4462 = 0.2231 mol of H2SO4.
Mass of H2SO4 required is -
W = 0.2231 × 98
W = 21.86 g
Therefore, 21.86 g of H2SO4 will be required.
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