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Answer:
Given ABC is a triangle in which altitudes BD and CE to sides AC and AB are equal
In ΔADB and ΔACE
∠ADB=∠AEC=90
0
(altitudes BD and CE to sides AC and AB)
BD=CE (Given altitudes are equal)
∠BAD=∠DAB (Common angle )
ΔABD≅ΔACE [by SAS congruence]
So AB=AC
Step-by-step explanation:
please mark as brainliest didi i am in class 6 only but I love maths and I know to solve it
Step-by-step explanation:
(i) In ∆ABE and ∆ACE, we have
∠AEB = ∠AFC
[Each 90° as BE ⊥ AC and CF ⊥ AB]
∠A = ∠A [Common]
BE = CF [Given]
∴ ∆ABE ≅ ∆ACF [By AAS congruency]
(ii) Since, ∆ABE ≅ ∆ACF
∴ AB = AC [By C.P.C.T.]
⇒ ABC is an isosceles triangle.
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