What is the constant of proportionality in the equation y=\dfrac{5}{9}xy= 9
5
xy, equals, start fraction, 5, divided by, 9, end fraction, x?
constant of proportionality ==equals
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mi krni call tual
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What is the constant of proportionality in the equation y=\dfrac{5}{9}xy= 9
5
xy, equals, start fraction, 5, divided by, 9, end fraction, x?
constant of proportionality ==equals
call nko kro pls
mi krni call tual
aaj
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Answer:
hi
Step-by-step explanation:
Circumference of the circular path
= 2πr=2×
22
7
×7=44 cm.
When it covers half the circumference the particle moves from A to B along the path ACB .
Hence distance covered =
44
2
=22 cm. Displacement is the length of straight line AB i.e., the diameter of the circle. Hence displacement is 2×7 = 14 cm from A to B
→
(AB)
.
(ii) On completion of the total circular path ACBA, the distance covered is equal to the circumference of the circle = 44 cm.
As the particle comes back to its initial position displacement is zero.
Answer:
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