What is the final molarity of a resultant solution when 125ml of 8% solution of caustic soda mixed with 125ml of 10% acetic acid solution?
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What is the final molarity of a resultant solution when 125ml of 8% solution of caustic soda mixed with 125ml of 10% acetic acid solution?
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Answer:
To find the final molarity of the resultant solution when two solutions are mixed, you can use the formula for dilution:
\(M_1V_1 = M_2V_2\)
Where:
- \(M_1\) is the initial molarity of the first solution
- \(V_1\) is the initial volume of the first solution
- \(M_2\) is the final molarity of the resultant solution
- \(V_2\) is the total volume after mixing both solutions
Let's calculate it step by step:
1. For the caustic soda solution:
- \(M_1\) (initial molarity) = 8%
- \(V_1\) (volume) = 125 ml
- Convert \(M_1\) to decimal: 8% = 0.08
2. For the acetic acid solution:
- \(M_1\) (initial molarity) = 10%
- \(V_1\) (volume) = 125 ml
- Convert \(M_1\) to decimal: 10% = 0.10
3. Calculate the total volume (\(V_2\)) after mixing both solutions:
\(V_2 = V_1 + V_1 = 125 ml + 125 ml = 250 ml\)
4. Now, use the dilution formula to find \(M_2\):
\(0.08 \cdot 125 ml = M_2 \cdot 250 ml\)
Solve for \(M_2\):
\(M_2 = \frac{0.08 \cdot 125 ml}{250 ml} = \frac{10 ml}{250 ml} = 0.04\)
So, the final molarity of the resultant solution is 0.04 M (Molar).