What is the gravitational force between two identical 50,000kg asteriods whose centre of mass are separated by 1000m?
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What is the gravitational force between two identical 50,000kg asteriods whose centre of mass are separated by 1000m?
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Verified answer
Answer:
F = G*Mm/r^2
Explanation:F = 6.64*10^-11 * 50000*50000/1000*1000
F= 0.166 N
**I am not sure of the calc but, this is the formula,verify the calc once......
Answer:
1
Explanation:
For this,you must know how to behave with Scientific Notations
Use the Newton's law of Gravitation formula
F
=
G
m
1
m
2
r
2
Here are the definition of the variables in the formula
F
=
Force of Gravity
G
=
Gravitational constant
=
6.67
⋅
10
−
11
N
m
2
k
g
2
m
1
=
Mass of the first object
=
5000 kg
m
2
=
Mass of second object=
5000 kg
r
=
Distance between the centres of the objects
=
100 m
We need to find
F
Before entering the values, we must convert the mass and the distance values into scientific notation (in the form of exponents)
m
1
=
5000 kg
=
5
⋅
1000
=
5
⋅
10
3
kg
m
2
=
5000 kg
=
5
⋅
1000
=
5
⋅
10
3
kg
r
=
100 m
=
10
2
m
Now, substitute the values in the formula
→
F
=
6.67
⋅
10
−
11
N
m
2
k
g
2
(
5
⋅
10
3
k
g
)
(
5
⋅
10
3
k
g
)
(
10
2
m
)
2
We have
(
5
⋅
10
3
k
g
)
(
5
⋅
10
3
k
g
)
=
(
5
⋅
10
3
k
g
)
2
→
F
=
6.67
⋅
10
−
11
N
m
2
k
g
2
(
5
⋅
10
3
k
g
)
2
10
4
m
2
→
F
=
6.67
⋅
10
−
11
N
m
2
k
g
2
5
2
⋅
10
6
k
g
2
10
4
m
2
→
F
=
6.67
⋅
10
−
11
N
m
2
k
g
2
25
⋅
10
6
k
g
2
10
4
m
2
Now we start to cancel
→
F
=
6.67
⋅
10
−
11
N
m
2
k
g
2
25
⋅
10
6
k
g
2
10
4
m
2
→
F
=
6.67
⋅
10
−
11
N
25
⋅
10
6
10
4
→
F
=
6.67
⋅
10
−
11
⋅
25
⋅
10
6
10
4
N
→
F
=
166.75
⋅
10
−
5
10
4
N
Move
10
4
to the Numerator
Remember that,when positive exponents in the Denominator go to the Numerator,the become as Negative exponents
→
F
=
166.75
⋅
10
−
5
⋅
10
−
4
N
→
F
=
166.75
⋅
10
−
9
⇒
F
=
1.6675
⋅
10
−
7