What is the value of (2° – 1+52 – 0)–? x 5?
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What is the value of (2° – 1+52 – 0)–? x 5?
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Answer:
L.H.S :5
2x−1
−25
x−1
can be written as
⇒5
2x−1
−5
2x−2
=5
2x−1
(1−
5
1
)
=5
2x−1
×
5
4
=5
2x−2
×4…eqn(1)
R.H.S :2500=25
2
×4
=5
4
×4…eqn(2)
We have, L.H.S =R.H.S
From equation 1 and 2
5
2x−2
×4=5
4
×4
⇒2x−2=4
⇒2x=6
⇒x=3