What must be added to 6003 to get a number exactly divisible by 27 ?
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What must be added to 6003 to get a number exactly divisible by 27 ?
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Answer:
Divide 6003 by 27 to get 222.3.
Take the next higher integer: 223.
Multiply 223*27 to get 6021.
Subtract 6003 from 6021 to get 18.
So you need to add 18 to 6003 to make it 6021 which is divisible by 27.
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