What number must be added to each of the numbers 25, 28, 5, 6 to get the numbers which are in proportion?
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What number must be added to each of the numbers 25, 28, 5, 6 to get the numbers which are in proportion?
What number must be added to each of the numbers 25, 28, 5, 6 to get the numbers which are in proportion?
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Answer: 27, 38, 7, 8
Let x be subtracted (27−x), (38−x), (7−x), (8−x)
So
(27−x)(7−x)=(38−x)(8−x)
189−27x−7x+x
2
=304−38x−8x+x
2
189−34x=304−46x
46x−34x=304−189
12x=115
x=
12
115
x=9.58
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