What should be added to 3x3 + x2 – 22x + 9 so that he
resultant when divided by (x+3) leaves remainder 7.
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What should be added to 3x3 + x2 – 22x + 9 so that he
resultant when divided by (x+3) leaves remainder 7.
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Answer:
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Step-by-step explanation:
2x+3
Let us divide 3x
3
+x
2
−22x+9 by 3x
2
+7x−6 by long division method as shown in the above image.
Therefore, the the remainder is −2x−3 that is −(2x+3)
Hence, −(2x+3) must be subtracted from 3x
3
+x
2
−22x+9 that is (2x+3) must be added to 3x
3
+x
2
−22x+9 so that the resulting polynomial is exactly divisible by 3x
2
+7x−6.