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Answer:
Given
a
2
=13 and a
5
=25
We know that
a
n
=a+(n−1)d
∴a
2
=a+(2−1)d
⇒13=a+(2−1)d
⇒a+d=13 ...(i)
and a
5
=a+(5−1)d
⇒25=a+4d
⇒a+4d=25 ...(ii)
Now, subtracting (i) from (ii), we get
3d=12
⇒d=4
Now a+d=13 [from (i)]
⇒a=9
Hence, a
7
=a+6d=9+6(4)
⇒a
7
=33