what will be the time period of a simple pendulum if the pendulum is taken to a place where the value of g is 4 times that on the surface of the earth?
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what will be the time period of a simple pendulum if the pendulum is taken to a place where the value of g is 4 times that on the surface of the earth?
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Explanation:
Acceleration due to gravity on the surface of the moon is
6
1
that of surface of the earth.
∴g
m
=
6
1
g
e
On earth, T
e
=2π
g
e
L
On Moon, T
m
=2π
g
m
L
∴
T
e
T
m
=
g
m
g
e
=
6
T
m
=
6
T
e
=
6
×4s=10s