What will be the unit digit of the squares of the following numbers?
(i) 81 (ii) 272 (iii) 799 (iv) 3853
(v) 1234 (vi) 26387 (vii) 52698 (viii) 99880
(ix) 12796 (x) 55555
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What will be the unit digit of the squares of the following numbers?
(i) 81 (ii) 272 (iii) 799 (iv) 3853
(v) 1234 (vi) 26387 (vii) 52698 (viii) 99880
(ix) 12796 (x) 55555
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Answer:
(i) 9
by making 9x9=81
(ii) 17x16
Verified answer
Answer:
1,4,1,9,6,9,4,0,6,5
Step-by-step explanation:
First I will solve (iii) 799 so you can understand well.
Take unit digit 9. square it : [tex]9^{2}[/tex] = 81 . Unit digit of 81 is 1.
so Ans= 1
Similarly,
(i) 81 ⇒ [tex]1^{2} =1[/tex] ⇒ Ans= 1
ii) 272 ⇒ [tex]2^{2} =4[/tex] ⇒ Ans= 4
(iii) 799 ⇒ [tex]9^{2} =81[/tex] ⇒ Ans= 1
(iv) 3853 ⇒ [tex]3^{2} =9[/tex] ⇒ Ans= 9
(v) 1234 ⇒ [tex]4^{2} =16[/tex] ⇒ Ans= 6
(vi) 26387 ⇒ [tex]7^{2} =49[/tex] ⇒ Ans= 9
(vii) 52698 ⇒ [tex]8^{2} =64[/tex] ⇒ Ans= 4
(viii) 99880 ⇒ [tex]0^{2} =0[/tex] ⇒ Ans= 1
(ix) 12796 ⇒ [tex]6^{2} =36[/tex] ⇒ Ans= 6
(x) 55555 ⇒ [tex]5^{2} =25[/tex] ⇒ Ans= 5
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