what will be the value of X in Pythagorean triplet (6,8,x).
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what will be the value of X in Pythagorean triplet (6,8,x).
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Answer:
let base = x
pythagorean triplet
H^2 = b^2 + p^2
we know that , longest side is the hypotenuse
so here H = 8
and we have assum the base = x
so p ( perpendicular ) = 6
now it is easy to solve the ques.
so taking formulae of pythagorean triplet
H^2 = b^2 + p^2
8^2 = x2 + 6^2
64 = x2 + 36
x2 = 64 - 36
x2 = 28
x = root28