When 20 g of lithium reacts with 30 g of oxygen, then calculate the mass of Li2O formed. Which is in excess
Li or O2, and by how many grams?
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When 20 g of lithium reacts with 30 g of oxygen, then calculate the mass of Li2O formed. Which is in excess
Li or O2, and by how many grams?
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Answer : The mass of excess reagent is, 7.04 grams
Explanation : Given,
Mass of Li = 20 g
Mass of = 30 g
Molar mass of Li = 6.94 g/mole
Molar mass of = 32 g/mole
First we have to calculate the moles of and .
Now we have to calculate the limiting and excess reagent.
The balanced chemical reaction is,
From the balanced reaction we conclude that
As, 4 moles of react with 1 mole of
So, 2.88 moles of react with moles of
That means, in the given balanced reaction, is a limiting reagent that limits the formation of products and is an excess reagent.
The excess reagent remains = 0.94 - 0.72 = 0.22 mole
The excess moles of = 0.22 mole
Now we have to calculate the mass of .
Therefore, the mass of excess reagent is, 7.04 grams
Answer:
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