When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(g) What is the mass of calcium carbonate needed to produce 41.0 L of carbon dioxide at STP?
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When heated, calcium carbonate decomposes to yield calcium oxide and carbon dioxide gas via the reaction CaCO3(s)→CaO(s)+CO2(g) What is the mass of calcium carbonate needed to produce 41.0 L of carbon dioxide at STP?
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Given:
Mass of carbon dioxide = 41.0 L
at STP = 22.4 L/mol
To find:
Mass of calcium carbonate ( = ?
Formula to be used:
Calculation:
Conclusion:
At STP, to produce 41.0 L of carbon dioxide, 183 g of calcium carbonate is required.