when Resistance 60 ohms and 90 ohms are connected in parallel .how to calculate equivalent resistance?
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when Resistance 60 ohms and 90 ohms are connected in parallel .how to calculate equivalent resistance?
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Answer:
equivalent resistance is 36 ohm
Explanation:
equivalent resistance in parallel=
Req= R1×R2/R1+R2
Req= 60×90/150=36 ohm
Given:-
To Find:-
Solution :-
Here we have:-
ㅤㅤㅤㅤ[tex] \small {\mathfrak {\underline { We \: know \: that \: :- }}}\\[/tex]
[tex] \sf\red{ {\dfrac {1}{R_p} = \dfrac {1}{R_1} + \dfrac {1}{R_2} + \dfrac {1}{R_3} +.. }}\\[/tex]
[tex]\small\underline{\pmb{\sf \:Substituting \: Values :-}}\\[/tex]
[tex]\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p} = \dfrac{1}{60} + \dfrac{1}{90}\\[/tex]
[tex]\sf \: \: \: \: \: \: \:\: \: :\implies\dfrac{1}{R_p} = \dfrac{3+2}{180}\\[/tex]
[tex]\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p} = \dfrac{5}{180}\\[/tex]
[tex]\sf \: \: \: \: \: \: \:\: \: :\implies \dfrac{1}{R_p }= \dfrac{1}{36}\\[/tex]
[tex]\sf \: \: \: \: \: \: \:\: \: \red{:\implies R_p = 36Ω}\\[/tex]
[tex]\therefore\:\underline{\textsf{ The equivalent resistance is \:\textbf{36Ω}}}.\\[/tex]