Which of the following is odd for every integer n ?
a. 2011n
b. n2 + 2011
c. n
d. 2n2 + 2011
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Which of the following is odd for every integer n ?
a. 2011n
b. n2 + 2011
c. n
d. 2n2 + 2011
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Answer:
[tex]n = odd \: number = 3[/tex]
[tex]2 {n}^{2} + 2011 = 2027 [/tex]
[tex]n = even \: number = 2[/tex]
[tex]2 {n}^{2} + 2011 = 2019[/tex]
SO THE VALUE OF 2n²+2011 IS ALWAYS ODD
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Answer:
n2+2011 is the answer
Step-by-step explanation: