Which of the following triplets are Pythagorean?
(i) (14, 48, 50)
(ii) (18, 79, 82)
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Answer:
2k, (k
2
+1) and (k
2
−1) form a Pythagorean triplet for any number, k > 1
Let 2k=14
Hence, k=7
and, k
2
+1=7
2
+1=49+1=50
and, k
2
−1=7
2
−1=49−1=48
Check the answers: 14
2
+48
2
=196+2304=2500=50
2
Hence, the triplet is 14,48,50
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