Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere
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Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere
Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere
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∆W = P ∆V
∆W = 2 × 10^5 (150 - 500) × 10^(-3)
∆W = -70 kJ
Question
Work done by air whem it expands from 500 litres to 150 litres at a constant pressure of 2 atmosphere
Solution
Given :
To finD
Work Done during expansion
[tex]\rule{300}{2}[/tex]
Work Done by a gas during a thermodynamic process is given as :
[tex]\huge{\boxed{\boxed{\sf{W = P \Delta{V}}}}}[/tex]
Change In Volume
[tex]\sf \Delta{V} = V_2 - V_1 \\ \\ \leadsto \sf \Delta{V} = - 350 L \\ \\ \leadsto \sf \Delta{V} = - 350 \times 10^3 m^{- 3}[/tex]
[tex]\rule{300}{2}[/tex]
Putting the values,we get :
[tex]\sf W = 2 \times 10^5 \times - 350 \times 10^{-3} \\ \\ \longrightarrow \sf W = - 7 \times 10^3 J[/tex]