write the value of identity (x-y)³
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( x - y )³ = x³ - y³ - 3xy ( x - y )
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Answer:
x−y)
3
=> (x-y)(x-y)(x-y)(x−y)(x−y)(x−y)
=> (x^2 + y^2 -2xy)(x-y)(x
2
+y
2
−2xy)(x−y)
=> x^3 - x^2y + xy^2 - y^3 - 2x^2y + 2xy^2x
3
−x
2
y+xy
2
−y
3
−2x
2
y+2xy
2
=> x^3 - y^3 -3x^2y + 3xy^2x
3
−y
3
−3x
2
y+3xy
2
=> < em > < strong > x^3 - y^3 - 3xy (x-y) < /strong > < /em ><em><strong>x
3
−y
3
−3xy(x−y)</strong></em>