Solve :- (2-x) < (2/x+1)
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(3-x)<x+3/x+1
(x-3)(x+1)/x+3>0
x=(-3,-1) union (3, infinity)
here is ur answer
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(2-x) < (2/x+1)
0<(2+x/x) -(2-x)
0<(2+x-2x+x^2)/X
0<(x^2-x+2)/X
D is -ve of (x^2-2x+2)
so answer is X belongs to(0,oo)
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I hope it helps
#Prem^_^