x^2-4x+3 find zeroes by spitting method
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Answer:
The zeroes are 1 and 3
Step-by-step explanation:
[tex]x {}^{2} - 4x + 3[/tex]
By splitting the middle term , we get,
[tex]x {}^{2} - x - 3x - 3[/tex]
[tex]x(x - 1) - 3(x - 1)[/tex]
[tex](x - 3)(x - 1)[/tex]
[tex](x - 1) \: and \: (x - 3) \: are \: equal \: \: to \: when \: x = 1 \: or \: x = 3[/tex]
Therefore the zeroes are
[tex]x = 1[/tex]
[tex]x = 3[/tex]
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