if x - (1/x)^2=36,find the value of x^2+ 1/x^2
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if x - (1/x)^2=36,find the value of x^2+ 1/x^2
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Step-by-step explanation:
We know that (x - 1/x)^2 = x^2 + 1/x^2 - 2
Since x^2 + 1/x^2 = 38,
(x - 1/x)^2 = 38 - 2
(x - 1/x)^2 = 36
(x - 1/x) = (36)^(1/2)
x - 1/x = 6 or -6
This is the required answer!
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