Give the excluded value
of the expression
x2-16/x2+8x+16
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Give the excluded value
of the expression
x2-16/x2+8x+16
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These are any values of x that make the denominator 0 (we can't have that, because that would be dividing by 0 ). So let's set 3−x equal to 0 ... x=3. So the excluded value for this expression is x=3 ... denominator to zero and solving gives the value that x