Factorise ( x^2+1/x^2)-4(x+1/x)+6
solve this who can I will mark brainlest
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With imaginary solutions, yes, as then it would be
(x+i)(x-i)=0
Which, with using the foil method, gets you:
x^2+xi-xi-i^2=x^2-i^2
Since i^2 equals -1, you can change the equation to be:
x^2-(-1)=x^2+1
Without imaginary solutions, however, this is unfactorable