x=asectheta and y=btantheta
then b square x square +a square y square
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HELLO DEAR,x=a.sec theta+b.tan theta ----------(1)
y=a.tan theta +bsec theta-----------(2)
equation (1) and (2) squaring and then subtracting from (1) to (2)
x^2-y^2=a(sec^2theta-tan^2theta) -b (sec^2theta-tan^2theta)
we know
sec^2x-tan^2x=1
now
x^2-y^2=a^2-b^2
I HOPE ITS HELP YOU DEAR,
THANKS