if x/y=(-1/3)^-3÷(2/3)^-4,find the value of (x/y)^-1
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if x/y=(-1/3)^-3÷(2/3)^-4,find the value of (x/y)^-1
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Verified answer
Given,
x/y = ((-1)/3)-3 ÷(2/3)-4
=(-1/3)-3 ÷2/3-4
=(-1/3)-9/2-4
= -1/3-9/2-4
=x/y= -53/6
Then,
(x/y)(-3x)/16y
= -53/6(-3/16× -53/6)
= -53/6×53/6×3/16.
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