(y3-27) expand eight standard
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Answer:
(y - 3)(y^2 + 3y + 9)
Step-by-step explanation:
y^3-27
= (y)^3 - (3)^3
= (y - 3)(y^2 + 3y + 3^2) [∵ using a^3 - b^3 = (a-b)(a^2 + ab + b^2)
= (y - 3)(y^2 + 3y + 9)
Step-by-step explanation:
in this we can see cubic power and then we have 27 which is the cube by that we have solved it. please follow my channel