Zeros of the polynomial x^2-8
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Answer:
4 and -4
Step-by-step explanation:
x^2+0x-8
x^2+4x-4x-8
x(x+4)-4(x+4)
(x+4)(x-4)
Therefore, the two zeroes,
x+4=0
x=-4 Ans
x-4=0
x=4 Ans
Answer:
[tex]\sqrt{-8}[/tex]
Step-by-step explanation:
The question asks you to find the zeroes of the polynomial.
Let p(x)= x^2-8
p(x)= 0 (To find the zero of the polynomial
x^2= -8
x= [tex]\sqrt{-8}[/tex]