Zn (s) + 2HCl (aq) → ZnCl2 (s) + H2 (g)
If 5.09 grams of zinc chloride are formed in this reaction, how many grams of zinc are required?
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Zn (s) + 2HCl (aq) → ZnCl2 (s) + H2 (g)
If 5.09 grams of zinc chloride are formed in this reaction, how many grams of zinc are required?
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Answer:
2.440g
Explanation:
Atomic mass of Zn=65.38
Molar mass ofZnCl2=136.68
(Calculations based on stoichiometry)
So,if Zn=65.38 gives ZnCl2=136.68
X g ofZn gives ZnCl2 = 5.09g
Cross multiply to get answer.
Hope it helps you
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